Name of Post: Jharkhand JSSC Junior Engineer JE Online Form 2022 (Jharkhand JSSC Junior Engineer JE Recruitment Online Form 2022)
Post Date: 09 February 2022 | 02:30 PM
Short Information: Jharkhand Staff Selection Commission (JSSC) has Recently Invited to Online Application Form for the Post of Junior Engineer in Civil, Electrical, Mechanical Trade (285 Post) Recruitment 2022. Those Candidates Who are Interested in this Vacancy and Have All Eligibility Criteria Can Read the Full Notification Before Apply Online.
Jharkhand Staff Selection Commission (JSSC)
Junior Engineer JE Recruitment 2022
Advt. No. : 06/2021 (JSSC JDLCCE)
|Important Dates||Application Fee|
|Online Application Start: 07 February 2022|
Registration Last Date: 08 March 2022
Fee Payment Last Date: 10 March 2022
Complete Form Last Date: 13 March 2022
Correction Last Date: 16 March 2022
Exam Date: Notified Soon
Admit Card: Notified Soon
|General, OBC, EWS: Rs. 100/-|
SC, ST Candidates: Rs. 50/-
|Pay the Exam Fee Through Credit Card, Debit Card, Net Banking Fee Mode.|
|Age Limit as on 01/08/2021|
|Min. Age: 18 Yrs.|
Max. Age: 35 Yrs.
Read the Notification for Age Relaxation.
|Candidates have an Engineering Diploma in Related Trade from Recognized Institute.|
Higher Education Qualified Candidates are also Eligible for This Vacancy.
Read the Notification for More Details.
Total Vacancy : 285 Post
|Post Name||General||BC||EBC||EWS||SC||ST||Total Post|
How to Apply Junior Engineer JE Recruitment 2022
- Jharkhand JSSC Junior Engineer JE Recruitment 2022.
- All Interested Candidates can Apply Online from 07/02/2022 to 08/03/2022.
- Read the Notification for More Details about JSSC Junior Engineer Recruitment.
- Kindly Fill Your Basic Details and Upload Your Photo, Sign, ID Proof and Other Documents.
- Check Your full Details Preview Before Submit Application Form.
- Pay Required Application Fee to Complete Form. If Fees are Asked.
- Take a Print Out of Submit Final Form for Further Process.
Interested Candidates can Read the Full Notification Before Apply Online.